Wie rechnen Sie # 2x ^ (2/3) - 5x ^ (1/3) - 3 = 0 #?

Nun das merken #3=5-2# daher

# 2x ^ (2/3) - 5x ^ (1/3) - 3 = 0 => 2x ^ (2/3) -5x ^ (1/3) - (5-2) = 0 => 2 * ( x ^ (2/3) -1) -5 (x ^ (1/3) -1) = 0 => 2 * (x ^ (1/3) + 1) * (x ^ (1/3) - 1) -5 (x ^ (1/3) -1) = 0 => (x ^ (1/3) -1) * [2 (x ^ (1/3) +1) -5] = 0 #