Wie können Sie den Nenner rationalisieren und # (sqrt (77)) / (sqrt (35)) # vereinfachen?

Auf diese Weise:

# sqrt77 / sqrt35 = sqrt77 / sqrt35 * sqrt35 / sqrt35 = sqrt (77 * 35) / 35 = #

# = sqrt (7 * 11 * 5 * 7) / 35 = (7 * sqrt55) / 35 = sqrt55 / 5 #.

ODER:

# sqrt77 / sqrt35 = sqrt (77/35) = sqrt (11/5) = sqrt11 / sqrt5 * sqrt5 / sqrt5 = sqrt55 / 5 #.

ODER:

# sqrt77 / sqrt35 = (sqrt7 * sqrt11) / (sqrt7 * sqrt5) = sqrt11 / sqrt5 * sqrt5 / sqrt5 = sqrt55 / 5 #.

#sqrt (77) / sqrt (35) #

# = (sqrt (11) sqrt (7)) / (sqrt (5) sqrt (7)) #

# = sqrt (11) / sqrt (5) #

# = sqrt (11) / sqrt (5) * sqrt (5) / sqrt (5) #

# = (sqrt (11) sqrt (5)) / 5 #

# = sqrt (55) / 5 #